If a variable has been unset with unset(), it will no
longer be set. isset() will return FALSE if testing a
variable that has been set to NULL. Also note that a NULL byte
("\0") is not equivalent to the PHP NULL constant.
If multiple parameters are supplied then isset() will
return TRUE only if all of the parameters are set. Evaluation goes from
left to right and stops as soon as an unset variable is encountered.
Parameters
var
The variable to be checked.
var
Another variable ..
...
Return Values
Returns TRUE if var
exists; FALSE otherwise.
Examples
Example #1 isset() Examples
<?php
$var = '';
// This will evaluate to TRUE so the text will be printed. if (isset($var)) { echo "This var is set so I will print."; }
// In the next examples we'll use var_dump to output // the return value of isset().
// The key 'hello' equals NULL so is considered unset // If you want to check for NULL key values then try: var_dump(array_key_exists('hello', $a)); // TRUE
?>
Notes
Warning
isset() only works with variables as passing anything
else will result in a parse error. For checking if
constants are set use the
defined() function.
Note: Because this is a
language construct and not a function, it cannot be called using
variable functions